I have an entity
@Data
@Entity
@Builder
@AllArgsConstructor
@NoArgsConstructor
@Table(name="component")
@Audited
public class Component implements Serializable {
private static final long serialVersionUID = 0L;
@Id
@GeneratedValue(strategy=GenerationType.IDENTITY)
private Long Id;
@Version
private Long version;
@Builder.Default
private Boolean activated = true;
private String name;
@ManyToOne
@JoinColumn(referencedColumnName="Id", nullable = true)
@Audited(targetAuditMode = RelationTargetAuditMode.NOT_AUDITED)
private Organisation organisation;
}
... and a repository interface:
@Repository
@RepositoryRestResource(exported = false)
public interface ComponentRepository extends JpaRepository<Component, Long>, JpaSpecificationExecutor<Component>, RevisionRepository<Component, Long, Integer> {
@Query("select c from Component c where 1 = ?#{@authorisation.isInternalUser() or @authorisation.isUserInOrg(#c) ? 1:0}")
Page<Component> findAll(@Nullable Specification<Component> spec, Pageable pageable);
}
My final goal is to filter out entities which the currently logged in user is not allowed to see, in an elegant way. I thought that the SpEL would be a nice way to do so, but I failed finding a way to pass the entity reference 'c' within the expression. Another alternative approach probably is to change the JPQL to something like this?
@Query("select c from Component c where c.organisation = ?#{ @authorisation.getCurrentUserOrganisation()} or 1 = ?#{@authorisation.isInternalUser() ? 1:0}")
Or maybe there is a way to annotate directly the entity with some SpEL?
I tried to debug the Spring sources and understand how it works, but all I saw was that in the SpEL context evaluation ... there was access only to the Pageable object and the JPA Specification.
Thank you in advance!
Create Specification<Component> spec
that do it:
authorisation.isInternalUser() or @authorisation.isUserInOrg(#c)
And use it with
Page<Component> findAll(@Nullable Specification<Component> spec, Pageable pageable);