Code after 'return' will never be executed

Question

I'm in my first week of coding. So far the youtube tutorial app I am making in swift is going perfectly apart from the above error message. Here is the code. I have rewritten this twice now exactly as they specify. I am trying to set up sounds to play with the card game we are making, the sounds play when cards are shuffled, turned around, matched or incorrectly matched. The error message is shown for "let soundURL" line of code, "Code after 'return' will never be executed". Please help?

class SoundManager {

   static var audioPlayer:AVAudioPlayer?

    enum SoundEffect {

        case flip
        case shuffle
        case match
        case nomatch

    }

   static func playSound(_ effect:SoundEffect) {

        var soundFilename = ""

        // Determine which sound effect we want to play
        //and set the appropriate file name

        switch effect {

        case .flip:
            soundFilename = "cardflip"

        case .shuffle:
            soundFilename = "cardflip"

        case .match:
            soundFilename = "dingcorrect"

        case.nomatch:
            soundFilename = "dingwrong"

        }
        // Get the path to the sound file inside the bundle
        let bundlePath = Bundle.main.path(forResource: soundFilename, ofType: "wav")

        guard bundlePath != nil else {
            print("Couldn't find sound file \(soundFilename) in the bundle")
            return



            // Create a URL object from this string path
            let soundURL = URL(fileURLWithPath: bundlePath!)


            do {
                // Create audio player object
                audioPlayer = try AVAudioPlayer(contentsOf: soundURL)

                // Play the sound
                audioPlayer?.play()
            }
            catch {
                // Could'nt create audio player object, log the error
                print("Could'nt create the audio player object for sound file \(soundFilename)")
            }


        }

    }
}

Answer 1

I believe you want your code to look something like this:

// Get the path to the sound file inside the bundle
let bundlePath = Bundle.main.path(forResource: soundFilename, ofType: "wav")

guard bundlePath != nil else {
    print("Couldn't find sound file \(soundFilename) in the bundle")
    return
}

// Create a URL object from this string path
let soundURL = URL(fileURLWithPath: bundlePath!)


do {
    // Create audio player object
    audioPlayer = try AVAudioPlayer(contentsOf: soundURL)

    // Play the sound
    audioPlayer?.play()
}
catch {
    // Could'nt create audio player object, log the error
    print("Could'nt create the audio player object for sound file \(soundFilename)")
}

If there is a guard statement with return inside its brackets, you do not want to put any code beneath the return and within the same brackets. None of the code below the return will execute. In my example, the following code is outside of the brackets, meaning it will execute so long as there is a value for bundlePath.