Write file creation date to a text file, in a single line

This may be easy but it's driving me nuts (2 whole hours spent already! I've tried dozens of things!).

I just need a single line bat script that reads a given file's creation date and writes it to a text file.

I've tried using the dir /T:C command, but it writes way too much info. For example:

dir /T:C "E:\TEST\test.mkv" >"E:\TEST\test.txt"

Writes this in the text.txt file:

Le volume dans le lecteur E s'appelle xxxxxxxx
Le numéro de série du volume est xxxxxxxx

Répertoire de E:\TEST

11/03/2018  20:45     1 947 028 131 test.mkv
               1 fichier(s)    1 947 028 131 octets
               0 Rép(s)  64 368 631 808 octets libres

And I'm only interested in the "11/03/2018 20:45" part.

EDIT: I could also settle for the previous dir /T:C syntax if we could add a bit of code to keep only line #6 of the output and write it to the same text file.

Solution

Here is my suggestion, which technically does and doesn't use only one line in the batch file, and uses VBScript.

<!-- :
@("%__AppDir__%cscript.exe" //NoLogo "%~f0?.wsf">"E:\TEST\test.txt")&Exit /B
-->
<Job><Script Language="VBScript">
Set o=CreateObject("Scripting.FilesystemObject")
Set f=o.GetFile("E:\TEST\test.mkv")
s=Left(f.DateCreated,Len(f.DateCreated)-3)
</Script></Job>

To remain on topic however here are some exactly one line batch file examples.

This method leverages powershell.exe:

@"%__AppDir__%WindowsPowerShell\v1.0\powershell.exe" -NoP "'{0:dd/MM/yyy}' -F(Get-Date(GI 'E:\TEST\test.mkv').CreationTime)">"E:\TEST\test.txt"

And this one uses WMIC.exe:

@For /F %%I In ('WMIC DataFile Where Name^="E:\\TEST\\test.mkv" Get CreationDate 2^>NUL^|Find "."')Do @Set "d=%%~nI"&(Call Echo %%d:~6,2%%/%%d:~4,2%%/%%d:~,4%% %%d:~8,2%%:%%d:~10,2%%)>"E:\TEST\test.txt"