I have the follwing string:
"[parameters('ECC_Shipment_Trigger_properties_pl_ecc_shipment_adls_sql_parameters_File_system')]"
and I would like to write a regular expression that return only:
parameters('ECC_Shipment_Trigger_properties_pl_ecc_shipment_adls_sql_parameters_File_system')
Keeping in mind that I only need content that starts as:
parameters('some string')
So far I have come up with (?<=[parameters(').+?(?=')) which only returns the text between single quotes.
for testing, I am using https://regexr.com/
How can I modify my current regex to get this result?
The positive lookbehind is an assertion (non consuming), so this part (?<=\[parameters\(') means that from the current position it asserts what is on the left is [parameters(.
Instead of a lookaround, you could use a capturing group and a negated character class matching any char except a ' instead.
The value is in the first capturing group.
\[(parameters\('[^']+'\))\]
If you want to use lookaround, this might be an option, asserting what is on the left is [ and what is on the right is ]
(?<=\[)parameters\('[^']+'\)(?=\])