Load fail directory file in XmlReader .NET 4.0

Question

This filename has character is  (0xE700).

when i read in XmlReader, i can't read it because the file name load changes character is %EE%9C%80

XmlReader reader = XmlReader.Create(fileName, settings);

Why  (0xE700) => %EE%9C%80!

Answer 1

it happens since XmlReader.Create treats first parameter as Uri. This is not obvious but you can get it from the method signature

XmlReader Create(string inputUri, XmlReaderSettings settings, XmlParserContext inputContext);

0xE700 is a special character that can't be used in the Uri and is escaped to %EE%9C%80!

However you can change the code and read the file content using FileStream e.g.

var fileName = string.Format("{0}test.xml", char.ConvertFromUtf32(0xE700));
File.WriteAllText(fileName, "<root><node /></root>");
using (var fileStream = new FileStream(fileName, FileMode.Open))
{
    using (var reader = XmlReader.Create(fileStream))
        reader.ReadStartElement();
}

new FileStream(fileName, FileMode.Open) will read file by name and will not encode the file name (as XmlReader.Create does).