How can I compare two hours in java?

Question

I want to calculate restaurant's opened hours. I have two string, for example:

String start_hour = "09:00";
String end_hour = "18:00";

And current hour for example:

    Calendar now = Calendar.getInstance();
    String current_hour = now.get(Calendar.HOUR_OF_DAY) + ":" + now.get(Calendar.MINUTE);

I calculate open hours with this method:

    public boolean isRestaurantOpenNow() {
            try {
                Calendar now = Calendar.getInstance();
                String current_hour = now.get(Calendar.HOUR_OF_DAY) + ":" + now.get(Calendar.MINUTE);
                String st_hour = "09:00";
                String en_hour = "18:00";
                @SuppressLint("SimpleDateFormat") final SimpleDateFormat format = new SimpleDateFormat("HH:mm");
                Date sth = null;
                sth = format.parse(st_hour);
                Date enh = format.parse(en_hour);
                Date nowh = format.parse(current_hour );
                if (nowh != null) {
                    if (nowh.before(enh) && nowh.after(sth)) {
                        // restaurant is open
                        return true;
                    } else {
                        // restaurant is close
                        return false;
                    }
                }
            } catch (ParseException ignored) {
            }
            return false;
        }

But I have some problem with that. This method working wrong when start_hour is "13:00" and end_hour "05:00". Because 05:00 hour from next day. How can I solve this problem?

Answer 1

instead of

nowh.before(enh) && nowh.after(sth)

use

nowh.before(enh) && nowh.after(sth) && sth.before(enh)
|| enh.before(sth) && !(nowh.before(enh) && nowh.after(sth))

Apart from that I think Calendar class is supposed to be used differently I assume...