I am trying to run this code, where it will count how many correct answers the user made.
But I don't know how. I think I should use the if or nested if's to do that. How can I do it?
This will ask for a user to input their correct answer, A, B, C, or D. Then I want to increment the n:
#include <stdio.h>
#include <conio.h>
#define p printf
#define s scanf
main () {
int Ttl;
char Ln, Mi, Fn,
A1, A2, A3, A4, A5, A6, A7, A8, A9, A10,
A11, A12, A13, A14, A15, A16, A17, A18, A19, A20;
clrscr();
p("\n)
p("\n\nEnter your last name: ");
s("%s", &Ln);
p("\nEnter your middle initial: ");
s("%s", &Mi);
p("\nEnter your first name: ");
s("%s", &Fn);
p("\nType the corresponding letter to each question.");
p("\n1.) Shortcut for'New Line'");
p("\n A. Ctrl + R C. Ctrl + M ");
p("\n B. Ctrl + QC D. Ctrl + KC ");
p("\nAnswer: ");
s("%s", A1);
p("\n2.) Shortcut for'Up Arrow Key'");
p("\n A. Ctrl + Z C. Ctrl + X ");
p("\n B. Ctrl + QC D. Ctrl + E ");
p("\nAnswer: ");
s("%s", A2);
p("\n3.) Shortcut for'Down Arrow Key'");
p("\n A. Ctrl + X C. Ctrl + E ");
p("\n B. Ctrl + C D. Ctrl + R ");
p("\nAnswer: ");
s("%s", A3);
p("\n4.) Shortcut for'Scroll Down'");
p("\n A. Ctrl + X C. Ctrl + R ");
p("\n B. Ctrl + E D. Ctrl + Z ");
p("\nAnswer: ");
s("%s", A4);
p("\n5.) Shortcut for'Page Up'");
p("\n A. Ctrl + K C. Ctrl + R ");
p("\n B. Ctrl + Q D. Ctrl + C ");
p("\nAnswer: ");
s("%s", A5);
p("\n6.) Shortcut for'Page Down'");
p("\n A. Ctrl + Q C. Ctrl + K ");
p("\n B. Ctrl + C D. Ctrl + Z ");
p("\nAnswer: ");
s("%s", A6);
p("\n7.) Shortcut for'Top of a File'");
p("\n A. Ctrl + KY C. Ctrl + KC ");
p("\n B. Ctrl + QC D. Ctrl + QR ");
p("\nAnswer: ");
s("%s", A7);
p("\n8.) Shortcut for'Bottom of a File'");
p("\n A. Ctrl + QC C. Ctrl + KY ");
p("\n B. Ctrl + QS D. Ctrl + KC ");
p("\nAnswer: ");
s("%s", A8);
p("\n9.) Shortcut for'Copy Block'");
p("\n A. Ctrl + QY C. Ctrl + KC ");
p("\n B. Ctrl + KY D. Ctrl + QC ");
p("\nAnswer: ");
s("%s", A9);
p("\n10.) Shortcut for'Delete Block'");
p("\n A. Ctrl + QR C. Ctrl + QC ");
p("\n B. Ctrl + KC D. Ctrl + KY ");
p("\nAnswer: ");
s("%s", A10);
p("\n11.) Hot Keys Command 'Saves the file currently being edited'");
p("\n A. F6 C. F2 ");
p("\n B. F4 D. F9 ");
p("\nAnswer: ");
s("%s", A11);
p("\n12.) Hot Keys Command'Loads a File'");
p("\n A. F7 C. F1");
p("\n B. F3 D. F8");
p("\nAnswer: ");
s("%s", A12);
p("\n13.) Hot Keys Command'Compiles and link the program'");
p("\n A. F4 C. F3 ");
p("\n B. F2 D. F9 ");
p("\nAnswer: ");
s("%s", A13);
p("\n14.) Hot Keys Command'Compiles file to .obj file'");
p("\n A. Alt + F9 C. Alt + F5 ");
p("\n B. Alt + F2 D. Alt + F7 ");
p("\nAnswer: ");
s("%s", A14);
p("\n15.) Hot Keys Command'Next error'");
p("\n A. Alt + F4 C. Alt + F9 ");
p("\n B. Alt + F7 D. Alt + F8 ");
p("\nAnswer: ");
s("%s", A15);
p("\n16.) Hot Keys Command'Previous error'");
p("\n A. Alt + F7 C. Alt + F9 ");
p("\n B. Alt + F3 D. Alt + F1 ");
p("\nAnswer: ");
s("%s", A16);
p("\n17.) Hot Keys Command'Activates the file menu'");
p("\n A. Alt + E C. Alt + C ");
p("\n B. Alt + F D. Alt + O ");
p("\nAnswer: ");
s("%s", A17);
p("\n18.) Hot Keys Command'Quit the Turbo C program'");
p("\n A. Alt + D C. Alt + P ");
p("\n B. Alt + C D. Alt + X ");
p("\nAnswer: ");
s("%s", A18);
p("\n19.) Hot Keys Command'Runs the program'");
p("\n A. Ctrl + F3 C. Ctrl + F2 ");
p("\n B. Ctrl + F5 D. Ctrl + F9 ");
p("\nAnswer: ");
s("%s", A19);
p("\n20.) Hot Keys Command'Switches between windows'");
p("\n A. F2 C. F6 ");
p("\n B. F4 D. F8 ");
p("\nAnswer: ");
s("%s", A20);
p("Thank you for answering the following question");
p("\nCalculating correct answers. Please wait...");
delay(5000);
p("\nYour total correct answer is: ");
p("\n\t\tEnd of the Program");
getche();
}
Here is an approach which uses an array of structures. This way you can keep as many parameters (related to the question) in the same place:
#include <stdio.h>
typedef struct {
const char *question;
int correct_answer;
int given_answer;
} question_t;
int main() {
question_t questions[] = {
{"how many wings does bird have?\n1) 55\t3) 3\n2) 5\t4) 2", 4},
{"how many heads does frog have?\n1) 55\t3) 3\n2) 1\t4) 2", 2},
{NULL},
};
int number_of_corrent_unswers = 0;
for(int i=0; questions[i].question != NULL; i++) {
puts(questions[i].question);
scanf("%d", &questions[i].given_answer);
if(questions[i].given_answer == questions[i].correct_answer) {
number_of_corrent_unswers++;
}
}
printf("number of correct answers: %d\n", number_of_corrent_unswers);
return 0;
}