id |car_id
0 | 32
. | 2
. | 3
. | 7
. | 3
. | 4
. | 32
N | 1
How do you choose the most and the least frequent numbers from the id_car column and present them in a new table with as it often appears?'car_id' and 'quantity'
mdata['car_id'].value_counts().idxmax()
Here's some code that will provide the most frequent ID and the three least-frequent IDs.
from collections import Counter
car_ids = [32, 2, 3, 7, 3, 4, 32, 1]
c = Counter(car_ids)
count_pairs = c.most_common() # Gets all counts, from highest to lowest.
print (f'Most frequent: {count_pairs[0]}') # Most frequent: (32, 2)
n = 3
print (f'Least frequent {n}: {count_pairs[:-n-1:-1]}') # Least frequent 3: [(1, 1), (4, 1), (7, 1)]
count_pairs has a list of pairs of (ID, count for that ID). It is sorted from most frequent to least frequent. most_common doesn't tell us the order of ties.
You may change the n to 1 if you only want any of the least-frequent IDs. I made it 3 so that you could see that three tied for least-frequent.