Take a simple nested list L
:
L <- list(lev1 = list(lev2 = c("bit1","bit2")), other=list(yep=1))
L
#$lev1
#$lev1$lev2
#[1] "bit1" "bit2"
#
#
#$other
#$other$yep
#[1] 1
And a vector giving a series of depths for each part I want to select from L
:
sel <- c("lev1","lev2")
The result I want when indexing is:
L[["lev1"]][["lev2"]]
#[1] "bit1" "bit2"
Which I can generalise using Reduce
like so:
Reduce(`[[`, sel, init=L)
#[1] "bit1" "bit2"
Now, I want to extend this logic to do a replacement, like so:
L[["lev1"]][["lev2"]] <- "new val"
, but I am genuinely stumped as to how to generate the recursive [[
selection in a way that will allow me to then assign to it as well.
Why cant you just do
L[[sel]] <- "new val"
well if you want to do the long way then
You could still use Reduce
with modifyList
or you could use [[<-
. Here is an example with modifyList
:
modifyList(L,Reduce(function(x,y)setNames(list(x),y),rev(sel),init = "new val"))
$lev1
$lev1$lev2
[1] "new val"
$other
$other$yep
[1] 1