I create a char array and want to pass a reference to it to a method which populates the array.
char binary[BYTE_LEN];
readBinaryInput(&binary);
The method is as follows.
void readBinaryInput(char *binaryString[]) {
printf("Enter an 8-bit binary string.\n");
int i;
for(i = 0; i < BYTE_LEN; i++) {
scanf("%s", binaryString[i]);
}
}
When I run the program calling the method, I get the following errors.
warning: passing argument 1 of 'readBinaryInput' from incompatible pointer type [-Wincompatible-pointer-types]
readBinaryInput(&binary);
note: expected 'char **' but argument is of type 'char (*)[8]'
void readBinaryInput(char *binaryString[]) {
I thought I was passing an address (&binary
) to the method for the pointer argument to point to. Why am I getting errors telling me that char **
is expected?
Try simply removing the &
from &binary
and the *
from char *binaryString[]
.
char binary[BYTE_LEN]
is already a pointer (essentially equivalent to char*
). It is a pointer to the first byte in your char array. Treat it as such.