I'm trying to make a print function in C++
that takes in variable numbers of arguments and prints them each on their own line, like:
template<typename Ty, typename... Types>
void println(Ty cur_line, Types... other_lines)
{
std::cout << cur_line << '\n';
println(other_lines);
}
void println() { std::cout << std::flush; }
However, if Ty
happens to be a std::vector<std::string>
, I want to treat it differently (because I want to print every element of the vector on its own line). I looked into partial specialization, but there doesn't seem to be much that I could find on doing so with parameter packs. Here's what I tried:
template<typename Ty, typename... Types>
void println(Ty cur_line, Types... other_lines)
{
std::cout << cur_line << '\n';
println(other_lines);
}
template<typename... Types>
void println<std::vector<std::string>, Types...>
(std::vector<std::string> cur_line, Types... other_lines)
{
for (const auto& line : cur_line)
{
std::cout << line << '\n';
}
println(other_lines);
}
void println() { std::cout << std::flush; }
However, I'm getting an MSVC error C2768: "'println': illegal use of explicit template arguments
".
Any suggestions or solutions would be warmly welcomed! For reference, I'm using Visual Studio 2019 Preview and its corresponding compiler version.
A simpler way would be to have a print function and overload that:
template < typename T >
void print(const T& line)
{
std::cout << line << '\n';
}
template < typename T >
void print(const std::vector<T>& line)
{
for (const auto& element : line)
{
print(element);
}
}
template<typename Ty, typename... Types>
void println(Ty cur_line, Types... other_lines)
{
print(cur_line);
println(other_lines);
}
void println() { std::cout << std::flush; }