How to counting the same word in a string
Input
Number of String
String1 = dadymathewdadreadad
String2 = sdgfghhjdjrjjyjjrtfdhe
Search = dad
Output
Number of dad in string1 = 3
Number of dad in string2 = 0
#include <iostream>
#include <string.h>
using namespace std;
int main() {
string str[50];
int n;
cin>>n;
for(int i = 0; i < n;i++) {
cin>>str[i];
}
for(int i = 0; i < 50;i++) {
if(substr(i,4) == "dad"){
n += 1;
}
}
cout<<n;
return 0;
}
In function 'int main()': [Error] 'substr' was not declared in this scope
Other Solution:
#include <iostream>
#include <string>
using namespace std;
int main(){
int n;
string s[50];
int c;
cin>>n;
for (int i=0;i<n;i++){
cin>>s[i];
}
for (int i=0;i<n;i++) {
c=0;
int found=s[i].find("jack");
while(found!=string::npos){
found=s[i].find("jack",found+1);
if(found) c++;
}
cout<<c<<endl;
}
}