It is possible to pipe data using unix pipes into a command-line php script? I've tried
$> data | php script.php
But the expected data
did not show up in $argv
. Is there a way to do this?
As I understand it, $argv
will show the arguments of the program, in other words:
php script.php arg1 arg2 arg3
But if you pipe data into PHP, you will have to read it from standard input. I've never tried this, but I think it's something like this:
$fp = readfile("php://stdin");
// read $fp as if it were a file