In MySQL 8, we can now use a JSON typed column and also use built-in functions like JSON_TABLE() but as I'm using in different scenarios sometimes I see results I did not expect.
Docs for JSON_TABLE() : https://dev.mysql.com/doc/refman/8.0/en/json-table-functions.html
Maybe JSON_TABLE is not the way to accomplish joining with a piece of JSON. There are some search functions MySQL provides, but nothing jumped out at me as an alternative to JSON_TABLE()
Docs for JSON search functions: https://dev.mysql.com/doc/refman/8.0/en/json-search-functions.html
Schema (MySQL v8.0)
CREATE TABLE USER (
NAME varchar(128) NOT NULL,
METADATA JSON NULL
);
INSERT INTO USER VALUES
('John', '[1,3]'),
('Jane', '[2]'),
('Bob', null),
('Sally', '[9]');
CREATE TABLE ROLES (
ID int NOT NULL,
NAME varchar(64) NOT NULL
);
INSERT INTO ROLES VALUES
(1, 'Originator'),
(2, 'Approver'),
(3, 'Reviewer');
Query #1 - Why is Bob not returned?
SELECT *
FROM USER,
JSON_TABLE(
USER.METADATA, "$[*]"
COLUMNS(ID int PATH "$" NULL ON ERROR NULL ON EMPTY)
) AS JSON_ROLE_LINK;
## Results ##
| NAME | METADATA | ID |
| ----- | -------- | --- |
| John | [1, 3] | 1 |
| John | [1, 3] | 3 |
| Jane | [2] | 2 |
| Sally | [9] | 9 |
Query #2
SELECT * FROM ROLES;
## Results ##
| ID | NAME |
| --- | ---------- |
| 1 | Originator |
| 2 | Approver |
| 3 | Reviewer |
Query #3 - Why are there no results?
SELECT *
FROM USER
JOIN ROLES ON ROLES.id IN (
SELECT ID FROM JSON_TABLE(
USER.METADATA, "$[*]"
COLUMNS(ID int PATH "$" NULL ON ERROR NULL ON EMPTY)
) AS JSON_ROLE_LINK
);
##There are no results to be displayed.
Query #4 - Not JOINing with an IN() returns correct results.
SELECT *
FROM USER,
JSON_TABLE(
USER.METADATA, "$[*]"
COLUMNS(ID int PATH "$" NULL ON ERROR NULL ON EMPTY)
) AS JSON_ROLE_LINK
JOIN ROLES ON ROLES.ID = JSON_ROLE_LINK.ID;
## Results ##
| NAME | METADATA | ID | ID | NAME |
| ---- | -------- | --- | --- | ---------- |
| John | [1, 3] | 1 | 1 | Originator |
| John | [1, 3] | 3 | 3 | Reviewer |
| Jane | [2] | 2 | 2 | Approver |
Query #5 - Where is Bob?
SELECT *
FROM USER,
JSON_TABLE(
USER.METADATA, "$[*]"
COLUMNS(ID int PATH "$" NULL ON ERROR NULL ON EMPTY)
) AS JSON_ROLE_LINK
LEFT JOIN ROLES ON ROLES.ID = JSON_ROLE_LINK.ID;
## Results ##
| NAME | METADATA | ID | ID | NAME |
| ----- | -------- | --- | --- | ---------- |
| John | [1, 3] | 1 | 1 | Originator |
| Jane | [2] | 2 | 2 | Approver |
| John | [1, 3] | 3 | 3 | Reviewer |
| Sally | [9] | 9 | | |
Query #6 - Why does a LEFT JOIN with IN() return the expected results when query #3 returned nothing?
SELECT *
FROM USER
LEFT JOIN ROLES ON ROLES.id IN (
SELECT ID FROM JSON_TABLE(
USER.METADATA, "$[*]"
COLUMNS(ID int PATH "$" NULL ON ERROR NULL ON EMPTY)
) AS JSON_ROLE_LINK
);
## Results ##
| NAME | METADATA | ID | NAME |
| ----- | -------- | --- | ---------- |
| John | [1, 3] | 1 | Originator |
| John | [1, 3] | 3 | Reviewer |
| Jane | [2] | 2 | Approver |
| Bob | | | |
| Sally | [9] | | |
Use ISNULL
property to create dummy json
SELECT *
FROM USER,
JSON_TABLE(
IFNULL(USER.METADATA,'[0]'), "$[*]"
COLUMNS(ID int PATH "$" NULL ON ERROR NULL ON EMPTY)
) AS JSON_ROLE_LINK;
#1 No JOINS with JSON_TABLE where is Bob?
SELECT *
FROM USER,
JSON_TABLE(
IFNULL(USER.METADATA,'[0]'), "$[*]"
COLUMNS(ID int PATH "$" NULL ON ERROR NULL ON EMPTY)
) AS JSON_ROLE_LINK;
#2 Verify our ROLE recrods exist
SELECT * FROM ROLES;
#3 Regular JOIN with JSON_TABLE inside the IN(), why are there no results?
SELECT *
FROM USER
JOIN ROLES ON ROLES.id IN (
SELECT ID FROM USER, JSON_TABLE(
USER.METADATA, "$[*]"
COLUMNS(ID int PATH "$" NULL ON ERROR NULL ON EMPTY)
) AS JSON_ROLE_LINK
);
#4 Regular JOIN with JSON_TABLE, returns expected results
SELECT *
FROM USER,
JSON_TABLE(
IFNULL(USER.METADATA,'[0]'), "$[*]"
COLUMNS(ID int PATH "$" NULL ON ERROR NULL ON EMPTY)
) AS JSON_ROLE_LINK
JOIN ROLES ON ROLES.ID = JSON_ROLE_LINK.ID;
#5 LEFT JOIN with JSON_TABLE, where is Bob?
SELECT *
FROM USER,
JSON_TABLE(
IFNULL(USER.METADATA,'[0]'), "$[*]"
COLUMNS(ID int PATH "$" NULL ON ERROR NULL ON EMPTY)
) AS JSON_ROLE_LINK
LEFT JOIN ROLES ON ROLES.ID = JSON_ROLE_LINK.ID;
#6 LEFT JOIN with JSON_TABLE inside the IN(), returns expected results
SELECT *
FROM USER
LEFT JOIN ROLES ON ROLES.id IN (
SELECT ID FROM JSON_TABLE(
IFNULL(USER.METADATA,'[0]'), "$[*]"
COLUMNS(ID int PATH "$" NULL ON ERROR NULL ON EMPTY)
) AS JSON_ROLE_LINK
);