I'm not sure if I will explain this correctly so apologies in advance.
I'm looking to put together a report that shows the number of times a site (central_site.site_code & central_site.site_name) appears in a report and then total this up for each month with a grand total at the end. The date to summarize into month values is job.actual_start_date
What I'm looking for is something like:
Site Code Site Name April May June July August Total
1234 HIGH STREET 2 4 3 3 2 14
3093 4TH AVENUE 10 5 8 8 7 38
The code I have got so far to produce all the information that I would like summarizing in the format above is:
select
central_site.site_code,
central_site.site_name,
job.actual_start_date
from
central_site
inner join job on job.site_code = central_site.site_code
inner join job_type on job.job_type_key = job_type.job_type_key
inner join job_status_log on job.job_number = job_status_log.job_number
where
job_type.job_type_code = 'G012' and
job_status_log.status_code = '5200'
I just don't know the syntax / formulas to be able to total each site up per month and then provide a total for the year.
I think you want conditional aggregation:
select cs.site_code, cs.site_name,
sum(case when extract(month from ?.datecol) = 1 then 1 else 0 end) as jan,
sum(case when extract(month from ?.datecol) = 2 then 1 else 0 end) as feb,
. . .,
count(*) as year_total
from central_site cs join
job j
on j.site_code = cs.site_code join
job_type jt
on j.job_type_key = jt.job_type_key join
job_status_log jsl
on j.job_number = js.job_number
where jt.job_type_code = 'G012' and
jsl.status_code = '5200' and
?.datecol >= date '2018-01-01' and
?.datecol < date '2019-01-01'
group by cs.site_code, cs.site_name;
This is assuming that "number of times" is simply a count. Your question doesn't specify *what column is used to specify the date. So, that element needs to be filled in.