Can someone give me the regex to match a valid AWS Cognito password - with numbers, special characters (their list), lower and upper case letters
The AWS Cognito default length limit is 6 characters and has it's own list of special characters
/^(?!\s+)(?!.*\s+$)(?=.*[A-Z])(?=.*[a-z])(?=.*[0-9])(?=.*[$^*.[\]{}()?"!@#%&/\\,><':;|_~`=+\- ])[A-Za-z0-9$^*.[\]{}()?"!@#%&/\\,><':;|_~`=+\- ]{8,256}$/
/ Indicates the start of a regular expression.^ Beginning. Matches the beginning of the string.(?!\s+) Disallows leading spaces.(?!.*\s+$) Disallows trailing spaces.(?=.*[a-z]) Requires lowercase letters.(?=.*[A-Z]) Requires uppercase letters.(?=.*[0-9]) Requires numbers.(?=.*[\^$*.[\]{}()?"!@#%&/\\,><':;|_~`=+\- ]) Requires at least one special character from the specified set. (The non-leading, non-trailing space character is also treated as a special character.)[A-Za-z0-9^$*.[\]{}()?"!@#%&/\\,><':;|_~`=+\- ]{8,256} Minimum 8 characters from the allowed set, maximum 256 characters.$ End. Matches the end of the string./ Indicates the end of a regular expression.The minimum character limit defaults to 8 but can be customised to a value between 6 and 99. The full length of a password however is limited to 256 characters (not 99).
https://docs.aws.amazon.com/cognito/latest/developerguide/user-pool-settings-policies.html
Cognito also has a "no leading or trailing spaces" rule in the default password requirements, but there are several docs out there that incorrectly state that "The space character is also treated as a special character". However, the current behaviour is actually "The non-leading, non-trailing space character is also treated as a special character".
To see the correct default password rules, view a user pool, click on the "Sign-in experience" tab, and click on "Contains at least 1 special character" to bring up a tooltip with the rules.