I am trying to develop some code for a college work and I have an algorithm that gives me the shortest path between two nodes in a graph. Please note that the nodes are Countries that have a capital.
Can anyone explain me how I can develop something that gives me the shortest path from country A to country B passing trough a list of capitals (countries)?
I have implemented a method that gives me the distance between two geographical points as well.
My initial thought was to order the list of capitals based on their distance to the country A and then sum all the distances of the shortest path between country A and the first of the list, then the first of the list and the third of the list and so on. Apparentely this is not correct.
public double shortestPathCapitals2(List<String> capitais, Pais pOrig, Pais pDest) {
double dist = 0;
LinkedList<Pais> shortPath = new LinkedList<Pais>();
LinkedList<String> temp = new LinkedList<>(capitais);
temp.addFirst(pOrig.getCapital());
temp.addLast(pDest.getCapital());
Collections.sort(temp, (c1, c2) -> (int) (distance(pOrig, shortestPathCapitals2(c2)) - distance(pOrig, obterPaisPorCapital(c1))));
for (int i = 0; i < temp.size() - 1; i++) {
Pais p1 = obterPaisPorCapital(temp.get(i));
Pais p2 = obterPaisPorCapital(temp.get(i + 1));
dist += shortestPath(p1, p2, shortPath);
shortPath.clear();
}
return dist;
}
Thank you.
problem description:
Given a graph with vertices V and edges E. We want to find a path P between Va and Vb such that:
pseudo-code:
function findPath(startVertex, endVertex, verticesToBeVisited, currentPath)
// check if we have reached the destination
if startVertex == endVertex:
/*
* there are multiple ways of reaching the destination
* calculate the length of the past (also called the cost)
* if the cost is lower than the current minimum, store the path
*/
cost = calculateCost(currentPath)
if cost < currentMinCost:
currentMinCost = cost
currentMinPath = currentPath
else:
/*
* if we have not reached the destination
* we need to try all possible next hops
* this algorithm uses recursion to do so
*/
for every vertex Vn that is a neighbour of startVertex:
/*
* this check prevents us from going
* Paris --> Rome --> Paris --> Rome (endlessly)
*/
if currentPath contains Vn:
continue
// add the next hop to our path
currentPath += Vn
// if this vertex needed to be visit, cross it out in the list
if verticesToBeVisited contains Vn:
verticesToBeVisited -= Vn
// recursion
findPath(Vn, endVertex, verticesToBeVisited, currentPath)
// clean up
if verticesToBeVisited contained Vn:
verticesToBeVisited += Vn
currentPath -= Vn