I just started using Gitlab's CI/CD feature. I need to create the zip file for the published items. The last two lines of the script should do the magic.
build:
stage: build
script:
- echo "Testing CI CD"
- git clone https://gitlab.io/common-dependencies.git
- git clone https://gitlab.io/sitecore-nuget.git
- nuget restore
- msbuild Common.SC.sln /property:Configuration=Release
/p:PublishProfile=C:\CICDArtifacts\Artifacts_Release.pubxml
- cd .\bin\Release
- '"C:\Program Files\7-Zip\7z.exe" a C:\CICDArtifacts\$CI_PROJECT_NAME-$CI_JOB_ID.zip'
But when the build triggers, i get the following error.
However when i executed below command in Gitlab runner it runs perfectly.
"C:\Program Files\7-Zip\7z.exe" a C:\CICDArtifacts\commonProject.zip'
It looks like i'm missing something here. Please help me to understand, how gitlab runner understands commands like 7z
, echo
, msbuild
etc.
Please note that, 7zip is installed and it is located under C:\Program Files\7-Zip\7z.exe
Your help much appreciated.
I have resolved the problem using below steps.
updated %PATH%
environment variable pointing to 7z.exe path.
Updated the script as below.
'- 7z a C:\CICDArtifacts\$CI_PROJECT_NAME-$CI_JOB_ID.zip'
Restarted the Gitlab runner as, Gitlab was not able to recognize the 7z
command after updating the environment variables.
Hope it is helpful for everyone.