Can't print the stringMatching pattern

Question

When i run this code I didn't get any error, but I can't print out my code on below.

I've tried to change condition places change but didn't work. Where is my mistake and how to fix it?

def stringMatching(text, pattern):
  for i in range (len(text) - len(pattern)):
  j = 0
  while j < len(pattern) & pattern[j] == text[i+j]:
    j = j + 1
  if j == len(pattern):
    return -1
string = "Chapter I. The quick brown fox jumped over the lazy dog."
substr = "over the"
print(stringMatching([string],[substr])) 

Answer 1

Assuming you're looking for substrings, you can just use the find() method like below:

print(string.find(substr))

if the result is > -1, it is a substring. You can also make a function if you want just a return 0/ -1 like so:

string = "Chapter I. The quick brown fox jumped over the lazy dog."
substr = "over the"
substr2 = "lazy hat"

def checkSubstring(string, substring):
    if string.find(substring) > -1:
        print("Within the Text")
        return 0
    else:
        print("Not within the Text")
        return -1

checkSubstring(string, substr)
checkSubstring(string, substr2)

which returns 0 and -1 respectively