I would like to create an empty data frame where the column names are coming from a character vector.
for example, if this was my vector:
vec <- letters[1:3]
I would like create an empty data frame like the following:
df <- tibble('a' = character(), 'b' = character(), 'c' = character())
however, I would like to iterate through the items in the vector to populate the dataframe names and not have to manually specify each one. In reality my vector has 40+ names.
I've tried the following by they don't work:
df <- tibble(vec[1:3])
df <- tibble(vec)
df <- tibble(for (i in 1:3){
vec[i]
})
Any help on this would be greatly appreciated!
You can create a named vector, vec, where the first argument sets the type of column you want. The rep("", 3) line says I want three character columns. Then the second argument is the vector of column names.
Use dplyr::bind_rows to convert this into tibble with one row. Then [0, ] selects zero rows, leaving it empty.
With this method, you can control the data type for each column easily.
library(dplyr)
vec <- setNames(rep("", 3), letters[1:3])
bind_rows(vec)[0, ]
# A tibble: 0 x 3
# ... with 3 variables: a <chr>, b <chr>, c <chr>
You can also use as_tibble if you transpose the named vector. I guess I use bind_rows because I usually have dplyr loaded but not tibble.
library(tibble)
vec <- setNames(rep("", 3), letters[1:3])
as_tibble(t(vec))[0, ]
# A tibble: 0 x 3
# ... with 3 variables: a <chr>, b <chr>, c <chr>
If you know all of the columns are of a single type (e.g., character), you can do something like this.
vec <- letters[1:3]
df <- bind_rows(setNames(rep("", length(vec)), vec))[0, ]