Is there any way to create a function that takes as argument a member function or a member?

Question

I have a function like this:

void f(std::ofstream& ostrm)
{
    auto a = Myglobal->getData1();
    ostrm << a;

    auto b = Myglobal->getData2();
    ostrm << b;

    auto c = Myglobal->m_data1;
    ostrm << c;

    auto d = Myglobal->m_data2;
    ostrm << d;

    //...
    auto z = Myglobal->getData1000();
    ostrm << z;
}

Is there any way to create a function that takes as argument a member function or a member to factorize this code?

(a, b, c, d and z are not the same type)

Answer 1

Yes, there is. One way is to turn void f into a function template, then pass the pointer to member of the desired data member or member function and let std::invoke (C++17, <functional> header) do the rest:

template <class PtrToMember>
void f(std::ofstream &ostrm, PtrToMember m){
    ostrm << std::invoke(m, Myglobal);
}

// call like this:

f(someStream, &T::getData1);
f(someStream, &T::m_data1);

where you should replace T by the the type of Myglobal of course. The nice thing about std::invoke is that it automatically handles all member (data or functions).