I use a password with a special char and symfony return an error "Malformed parameter "url"."
How can i use this kind of password ? foo?bar
I try with variables like that
DATABASE_USER='foo'
DATABASE_PASSWORD='foo?bar'
DATABASE_URL=mysql://${DATABASE_USER}:${DATABASE_PASSWORD}@100.100.100.100:3306/db
But is not working
as the variable name suggests, the DATABASE_URL
has to be a URL. that is, everything that is a character with meaning in URLs (for example #
, ?
, :
, ...) has to be URL-encoded.
For example ?
has to be encoded as %3F
if it is supposed to appear in a different meaning than to mark the query. There are lots of tools online to URL-encode stuff...