Given the following list:
l1 = [0,1000,5000,10000,20000,30000,40000,50000]
I know I can create chunks of it by looking at every consecutive pair of numbers:
def chunker(seq, size):
return (seq[pos:pos + size] for pos in range(0, len(seq), size))
for group in chunker(l1, 2):
print(group)
This returns:
[0, 1000]
[5000, 10000]
[20000, 30000]
[40000, 50000]
How can I make sure that overlapping intervals, such as [1000,5000], are also included?
Expected output:
[0, 1000]
[1000, 5000]
[5000, 10000]
[10000, 20000]
[20000, 30000]
[30000, 40000]
[40000, 50000]
You unnecessarily iterate over range with the step size. This way you prevent groups starting in place where the other group finishes. This code should work:
l1 = [0,1000,5000,10000,20000,30000,40000,50000]
def chunker(seq, size):
return (seq[pos:pos + size] for pos in range(0, len(seq)))
for group in chunker(l1, 2):
print(group)
The output is:
[0, 1000]
[1000, 5000]
[5000, 10000]
[10000, 20000]
[20000, 30000]
[30000, 40000]
[40000, 50000]
[50000]
You may skip the last element if that is what you wish, but depends on your requirement.