Given the problem description:
More specifically, the problem involves specifically the decorated annulus. The problem I am having is to separate the lightly shaded triangle from the dark shaded triangles.
I have produced code (based on a previous example) that produces a circular annulus. However, the triangles are together rather than separate, and produce the same color.
Here is the code that I have produced so far:
///////////////////////////////////////////////////////////////////////////////////////////
// circularAnnuluses.cpp
//
// This program draws three identical-looking circular annuluses in three different ways -
// see comments below.
//
// Interaction:
// Press the space bar to toggle between wirefrime and filled for the lower annulus.
//
// Sumanta Guha.
///////////////////////////////////////////////////////////////////////////////////////////
#include <cstdlib>
#include <cmath>
#include <iostream>
#ifdef __APPLE__
# include <GL/glew.h>
# include <GL/freeglut.h>
# include <OpenGL/glext.h>
#else
# include <GL/glew.h>
# include <GL/freeglut.h>
//# include <GL/glext.h>
#pragma comment(lib, "glew32.lib")
#endif
#define PI 3.14159265
#define N 6.0 // Number of vertices on the boundary of the disc.
using namespace std;
// Globals.
static int isWire = 0; // Is wireframe?
// Drawing routine.
void drawScene(void)
{
float angle;
int i;
glClear(GL_COLOR_BUFFER_BIT | GL_DEPTH_BUFFER_BIT); // Clear the buffers including
// the depth buffer.
glPolygonMode(GL_FRONT, GL_FILL);
// Lower circular annulus: with a true hole.
if (isWire) glPolygonMode(GL_FRONT, GL_LINE); else glPolygonMode(GL_FRONT, GL_FILL);
glBegin(GL_TRIANGLE_STRIP);
for (i = 0; i <= N; ++i)
{
angle = 2 * PI * i / N;
glColor3f(1.0, 0.0, 0.0);
glVertex3f(50 + cos(angle) * 10.0, 50 + sin(angle) * 10.0, 0.0);
glColor3f(0, 1, 0);
glVertex3f(50 + cos(angle) * 20.0, 50 + sin(angle) * 20.0, 0.0);
}
glEnd();
// Write labels.
glColor3f(0.0, 0.0, 0.0);
glFlush();
}
// Initialization routine.
void setup(void)
{
glClearColor(1.0, 1.0, 1.0, 0.0);
}
// OpenGL window reshape routine.
void resize(int w, int h)
{
glViewport(0, 0, w, h);
glMatrixMode(GL_PROJECTION);
glLoadIdentity();
glOrtho(0.0, 100.0, 0.0, 100.0, -1.0, 1.0);
glMatrixMode(GL_MODELVIEW);
glLoadIdentity();
}
// Keyboard input processing routine.
void keyInput(unsigned char key, int x, int y)
{
switch (key)
{
case ' ':
if (isWire == 0) isWire = 1;
else isWire = 0;
glutPostRedisplay();
break;
case 27:
exit(0);
break;
default:
break;
}
}
// Routine to output interaction instructions to the C++ window.
void printInteraction(void)
{
cout << "Interaction:" << endl;
cout << "Press the space bar to toggle between wirefrime and filled for the lower annulus." << endl;
}
// Main routine.
int main(int argc, char** argv)
{
printInteraction();
glutInit(&argc, argv);
glutInitContextVersion(4, 3);
glutInitContextProfile(GLUT_COMPATIBILITY_PROFILE);
glutInitDisplayMode(GLUT_SINGLE | GLUT_RGBA | GLUT_DEPTH);
glutInitWindowSize(500, 500);
glutInitWindowPosition(100, 100);
glutCreateWindow("DecoratedAnnulus.cpp");
glutDisplayFunc(drawScene);
glutReshapeFunc(resize);
glutKeyboardFunc(keyInput);
glewExperimental = GL_TRUE;
glewInit();
setup();
glutMainLoop();
}
The section of code where the problem lies is in the 'drawscene' function. I believe there should be two different for loops to separate the triangles from one another, but whenever I try to split the for loop it produces a monster of a shape.
I'm not exactly sure where to begin to complete this last problem.
As mentioned in the other answer, a possibility is to switch to flat shading mode by glShadeModel
.
But note, you've also to offset the vertex coordinates of the outer circle:
glShadeModel( GL_FLAT );
glBegin(GL_TRIANGLE_STRIP);
for (i = 0; i <= N; ++i)
{
angle1 = 2 * PI * i / N;
angle2 = 2 * PI * (i+0.5) / N;
glColor3f(1.0, 0.0, 0.0);
glVertex3f(50 + cos(angle1) * 10.0, 50 + sin(angle1) * 10.0, 0.0);
glColor3f(0, 1, 0);
glVertex3f(50 + cos(angle2) * 20.0, 50 + sin(angle2) * 20.0, 0.0);
}
glEnd();
The other possibility is to draw the inner and outer triangles with the primitive type GL_TRIANGLES
in 2 separate loops:
glShadeModel( GL_SMOOTH );
glBegin(GL_TRIANGLES);
glColor3f(1.0, 0.0, 0.0);
for (i = 0; i <= N; ++i)
{
angle1 = 2 * PI * i / N;
angle2 = 2 * PI * (i+0.5) / N;
angle3 = 2 * PI * (i+1) / N;
glVertex3f(50 + cos(angle1) * 10.0, 50 + sin(angle1) * 10.0, 0.0);
glVertex3f(50 + cos(angle2) * 20.0, 50 + sin(angle2) * 20.0, 0.0);
glVertex3f(50 + cos(angle3) * 10.0, 50 + sin(angle3) * 10.0, 0.0);
}
glEnd();
glBegin(GL_TRIANGLES);
glColor3f(0, 1, 0);
for (i = 0; i <= N; ++i)
{
angle1 = 2 * PI * (i-0.5) / N;
angle2 = 2 * PI * i / N;
angle3 = 2 * PI * (i+0.5) / N;
glVertex3f(50 + cos(angle1) * 20.0, 50 + sin(angle1) * 20.0, 0.0);
glVertex3f(50 + cos(angle2) * 10.0, 50 + sin(angle2) * 10.0, 0.0);
glVertex3f(50 + cos(angle3) * 20.0, 50 + sin(angle3) * 20.0, 0.0);
}
glEnd();
Both methods generate the following image:
If you want a more "circular" look, then you've to tessellate the segments along the inner or outer circle. Use the primitive type GL_TRIANGLE_FAN
(see Triangle primitives) to draw a single segment:
int N2 = 10;
glShadeModel( GL_SMOOTH );
# draw the red segments
glColor3f(1.0, 0.0, 0.0);
for (int i = 0; i <= N; ++i)
{
float angle1 = 2 * PI * i / N;
float angle2 = 2 * PI * (i+0.5) / N;
float angle3 = 2 * PI * (i+1) / N;
# draw a single red segment
glBegin(GL_TRIANGLE_FAN);
glVertex3f(50 + cos(angle2) * 20.0, 50 + sin(angle2) * 20.0, 0.0);
for (int j = 0; j <= N2; ++j)
{
float a = angle1 + (angle3 - angle1) * (float)j / (float)N2;
glVertex3f(50 + cos(a) * 10.0, 50 + sin(a) * 10.0, 0.0);
}
glEnd();
}
# draw the green sgements
glColor3f(0, 1, 0);
for (int i = 0; i <= N; ++i)
{
float angle1 = 2 * PI * (i-0.5) / N;
float angle2 = 2 * PI * i / N;
float angle3 = 2 * PI * (i+0.5) / N;
# draw a single green segment
glBegin(GL_TRIANGLE_FAN);
glVertex3f(50 + cos(angle2) * 10.0, 50 + sin(angle2) * 10.0, 0.0);
for (int j = 0; j <= N2; ++j)
{
float a = angle1 + (angle3 - angle1) * (float)j / (float)N2;
glVertex3f(50 + cos(a) * 20.0, 50 + sin(a) * 20.0, 0.0);
}
glEnd();
}