I need to find the file size of a video size that has 1 hour and 45 minutes, 24bit color encoding per pixel and has 1920x1080 resolution.
So my calculations were like this:
Total Pixels = 1920 * 1080 = 2073600
Size of Each Frame = Total Pixels * 24 bit = 2073600 * 24 = 49 766 400 bits
Video Length = 1 hour and 45 minutes = 105 minutes = 6300 seconds
Video Size = Framerate * Size of Each frame * Video Length
= 24 * 49766400 * 6300 = 7 524 679 680 000 bits
I don't know how to express the conversion from bits to gigabytes but I just checked the Video Size in gigabytes using a converter and it gave me a result of 875.99 GB. This does not seem right, so I'm asking here if I missed some calculation.
Note: I will need this to know what minimal speed a bandwidth must have to transfer this file in 12 seconds.
Assuming there is no compression...
Converting size form bits to bytes:
7524679680000 bits equal 7524679680000/8 bytes = 940584960000 Bytes.
Converting size from bytes to Giga Bytes:
In computers systems:
1 KByte = 1024 Bytes
1 MByte = 1024 KByte
1 GByte = 1024 MByte = 1024*1024*1024 Bytes = 2^30 Bytes
940584960000 Bytes equal 940584960000/2^30 GB equal 875.988 GB
Computing required bandwidth (without compression):
bandwidth = size / time = 7524679680000[bits]/12[sec] = 627056640000 bits/sec
Converting from bits/sec to Gbit/sec:
Remark: Bandwidth is usually measured in Giga bit per second (not Giga Byte per second).
According to Wikipedia's Data-rate units page Gbit/s is 10^9 bits/sec (not 2^30 bits/sec).
627056640000 bits/sec equal 627056640000/10^9 Gbit/sec equal 627.0566 Gbit/sec.
Well... with current technology, even RAM bandwidth is too low (assuming you have 2TB RAM, and you try to copy the data in the RAM, it's going to take more than 12 seconds).