I have the following versions of negating some integer value (in R12) in assembly in msp430 :
inv R12
inc R12
this is according to the manual and I think this will work the same?
inv R12
add #1, R12
But will this work and why not? :
sub #1, R12
inv R12
Still new to this and thank you for any help!
INC dst
is emulated with ADD #1, dst
, so the first two versions are exactly the same.
As for the third version: In the two's complement representation, inverting all bits computes the negative minus one, so you are computing (−x − 1) + 1 or −(x + 1) + 1, which is indeed the same.
And if you want a more practical demonstration, just use brute force:
#include <assert.h>
#include <stdint.h>
#include <stdio.h>
int main()
{
for (uint32_t i = 0; i < 0x10000; i++) {
uint16_t input = i;
uint16_t output1 = (~input) + 1;
uint16_t output2 = ~(input - 1);
assert(output1 == output2);
}
puts("it works!");
return 0;
}