Return a function with parameters

Question

I am trying to make a function that returns itself with parameters.

Def a (x,y):
   *code*
   Return a(x,y)

this returns an error when I try to run it.

>>> a(1,2)
RecursionError: maximum recursion depth exceeded

What I want is

>>> a(1,2)
a(1,2)

It there a way to return the function with parameters?

I know it can be done but I don’t know how to do it

>>> datetime.time(0,0)
Datetime.time(0,0)

Edit: Preferably I would like not to have to import any modules

Answer 1

I think you've misunderstood what is "returned" when you call the following row:

>>> datetime.time(0,0)
Datetime.time(0,0)

The original call datetime.time(0,0) creates a datatime-object to the console. Because you're not saving the returned object, the console automatically calls for the class-method called __repr__.

To replicate the behavior we can create the following class:

>>> class a:
...   def __init__(self, x,y):
...     self.x = x
...     self.y = y
...   def __repr__(self):
...     return "a({},{})".format(self.x, self.y)
...
>>> a(1,2)
a(1,2)