How to get the full source of a link using selenium

Question

I'm using selenium RC and want to get all the attributes and all. Something like:

link = sel.get_full_link('//a[@id="specific-link"]')

and the result would of:

print link

would be:

<a id="specific-link" name="links-name" href="url"> text </a>

Is this possible?

thanks

Answer 1

Here's a fancier solution:

sel.get_eval("window.document.getElementByID('ID').innerHTML")

(don't be picky with me on the javascript..)