how to assign array of struct to class variable without memcpy

Question

I'm creating a class were doing something with an array of struct, but the problem is I cannot assign array reference to the object.

already trying to find the solution, but only works with copying the entire array to the object variable with memcpy, how to do this differently without copying the array?

#include <math.h>
#include <stdio.h>
#include <stdlib.h>
#include <string.h>

#define arrayLength(array) (size_t)((sizeof array) / (sizeof array[0]))

typedef struct someStruct {
  int id;
  char *name;
} someStruct;

class someClass {
private:
  someStruct *list;

public:
  someClass(someStruct const *const listData) { list = listData; }
};


int main() {
  someStruct list[255] = {
      {1, "one"},
  };

  someClass object(list);

  return 0;
}

error: invalid conversion from 'const someStruct*' to 'someStruct*' [-fpermissive] someClass(someStruct const *const listData) { list = listData; }

Update: At the time this question was initially asked. I'm still a newbie in learning C/C++. In this context, I'm forcing to how I code in Python to C/C++ without knowing the pointer enough.

Answer 1

You are supplying a const pointer, then assigning a non-const pointer to that const pointer. The compiler is not letting you downgrade const to non-const.

Make someClass's list a const pointer, or remove the const qualifiers from the initializer parameters.