Regex to find partially matched special characters in python

Question

I have some strings, and want to match the special characters(@@,$$,><,...,^) from the string,

a='aaa@@aa;aa$$aaa;aa><aaa;aa....aaa;aaa^aa'

match=re.findall('@@|$$|><|....|^', a)
print(match)

I want following o/p:

@@
$$
><
....
^

Answer 1

You can try something like below:

>>> a='aaa@@aa;aa$$aaa;aa><aaa;aa....aaa;aaa^aa'
>>> match=re.findall('@{2}|[$]{2}|><|[.]{4}|\^', a)
>>> match
['@@', '$$', '><', '....', '^']

Edit: When you enclose a special character inside brackets it loses its meaning, e.g., [.] will match the . character.