Java - BubbleSort - Is there a way for me to have the same input multiple times?

Question

I'm trying to sort cards by their value using BubbleSort, but have got some problems when using the same card or a card with a similar value.

import java.util.HashMap;

public class KartenSort {

private int zwei = 2;
private int drei = 3;
private int vier = 4;
private int fuenf = 5;
private int sechs = 6;
private int sieben = 7;
private int acht = 8;
private int neun = 9;
private int zehn = 10;
private int koenig = 10;
private int dame = 10;
private int bube = 10;
private int ass = 11;

public int[] liste ={drei,zwei,fuenf,vier,koenig,sieben,ass};
public int[] sortieren(){

    int unsortiert;
    for(int sortiert = 0; sortiert < liste.length -1; sortiert++){

        if(liste[sortiert] <= liste[sortiert+1]){
            continue;
        }

    unsortiert = liste[sortiert];
        liste[sortiert] = liste[sortiert+1];
        liste[sortiert+1] = unsortiert;
        sortieren();
    }
return  liste;
}

public static void  main (String[] args){

    HashMap<Integer,String> numbers = new HashMap<>();
    numbers.put(2, "zwei");
    numbers.put(3, "drei");
    numbers.put(4, "vier");
    numbers.put(5, "fuenf");
    numbers.put(6, "sechs");
    numbers.put(7, "sieben");
    numbers.put(8, "acht");
    numbers.put(9, "neun");
    numbers.put(10, "zehn");
    numbers.put(10, "koenig");
    numbers.put(10, "dame");
    numbers.put(10, "bube");
    numbers.put(11, "ass");

    KartenSort bs = new KartenSort();
    int[] array = bs.sortieren();
    for (int sortiert=0;sortiert < array.length; sortiert++){
        System.out.println(numbers.get(array[sortiert]));
    }

}

}

Instead of it printing out "koenig", "dame", etc... all cards with the value 10 will show as "bube". Is there maybe a way to map them?

Answer 1

This statements:-

if(liste[sortiert] < liste[sortiert+1]){
  continue;
}

When both operands same value it will be evaluated to false. End up recursive sortieren() calls without array index increase. Change to <= operator for continue statement to work. For example:-

if(liste[sortiert] <= liste[sortiert+1]){
  continue;
}