use the output of rename to make directory wo renaming the files

I have a directory with multiple files that they all end as "_1.fastq.gz" or "_2.fastq.gz"

ERR3258060_1.fastq.gz  
ERR3258060_2.fastq.gz  
ERR3258861_1.fastq.gz  
ERR3258861_2.fastq.gz

What I want to do (in a first step) is take all the files that end in _1.fastq.gz keep the first 10 characters of the filename (the ERR32.....) and make a directory with that

therefore the directories would look like ERR3258060 ERR3258861

using bash I have so far tried the following

for f in *_1.fastq.gz
do
echo $f | rename -n 's/_1.fastq.gz//' * | mkdir
done

The command produces the filename the way i want it but mkdir will not take the output of the rename, it will simply say "missing operand" how can I make mkdir take the result of the previous command?

thanks

Solution

No need to use rename. You can just use sed. In the first step, you create the directory name and then use it in mkdir.

for f in *_1.fastq.gz
do
    dir=$(echo $f | sed 's/_1.fastq.gz//')
    mkdir $dir
done