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hexbyteuint

I don't Understand - *(uint*)((byte*)p + Offset)

I am having trouble understanding this code and would like a good explanation.

The following function takes in a hex file and modifies the address without overwriting everything else.

Can someone explain to me how its doing that?

unsafe void WriteUint32(void* p, int Offset, uint value)
        {
            *(uint*)((byte*)p + Offset) = value;
        }
Solution

  • If we ignore Offset, you have

    *(uint*)((byte*)p) = value;

    which is just assigning value to what p points to, interpreted as a uint.

    Adding Offset just changes the pointer to where value is being assigned.