How do I determine the optimal number of clusters while using hierarchical clustering. If I am just having the distance matrix as I am measuring only pairwise distances (levenshtein distances), how do I find out the optimal number of clusters? I referred to other posts they all use k-means, hierarchical but not for string type of data as shown below. Any suggestions on how to use R to find the number of clusters?
set.seed(1)
rstr <- function(n,k){ # vector of n random char(k) strings
sapply(1:n,function(i) {do.call(paste0,as.list(sample(letters,k,replace=T)))})
}
str<- c(paste0("aa",rstr(10,3)),paste0("bb",rstr(10,3)),paste0("cc",rstr(10,3)))
# Levenshtein Distance
d <- adist(str)
rownames(d) <- str
hc <- hclust(as.dist(d))
Several statistics can be used.
Look for example at the WeightedCluster package that can compute and plot a series of such statistics.
To illustrate, you get the optimal number of groups for each available statistics as follows:
library("WeightedCluster")
hcRange <- as.clustrange(hc, diss=as.dist(d), ncluster=6)
summary(hcRange)
## 1. N groups 1. stat
## PBC 3 0.8799136
## HG 3 1.0000000
## HGSD 3 0.9987651
## ASW 3 0.4136550
## ASWw 3 0.4722895
## CH 3 8.3605263
## R2 6 0.4734561
## CHsq 3 20.6538462
## R2sq 6 0.6735039
## HC 3 0.0000000
You can also plot the statistics (here we show the Average silhouette width, ASWw, Huber's Gamma, HG, and the Point biserial correlation) for all the computed solutions
plot(hcRange, stat = c("ASWw", "HG", "PBC"), lwd = 2)
The better solution seems to be the three groups solution.