Determine if a variable is of a lazy type

Question

Quick question - is there any 'prettier' way to determine if a variable was lazily initialized than:

var paramType = param.GetType();
if (paramType.FullName.Contains("System.Lazy")) 
{
    ...
}

I know it's not something really recommended to be checked, but there is a particular need to differentiate it.

Answer 1

Try this:

if (paramType.IsGenericType && paramType.GetGenericTypeDefinition() == typeof(Lazy<>))

It should return true if param is a Lazy<T> (and paramType is param.GetType()).