The problem is this. I am sending a music file. I keep getting error 422
. For this reason, it seems I am not able to properly position my body
this is my output from the console
Content-Disposition: form-data; name="Content-Disposition: form-data;
name="audio[file]"; filename="tr.mp3""
Content-Transfer-Encoding: binary
Content-Type: audio/mpeg
Content-Length: 6028060
and my code
@Multipart
@Headers({"Content-Type: multipart/form-data;", "Accept:application/json, text/plain, */*"})
@POST("audios")
Call<SoundResponse> saveSound(@Part ("Content-Disposition: form-data; name=\"audio[file]\"; filename=\"tr.mp3\"") RequestBody file,
@Query("auth_token") String authToken);
and called this method
RequestBody body = RequestBody.create(MediaType.parse("audio/mpeg"), file);
GeoService.saveSound(body,SoundResponseCallback, getAuthToken());
I also found this stuff
Send file to server via retrofit2 as object
It seems to me that the problem is that the field looks like this "audio [file]"
Thank you for your help
i found the answer to the question.The solution was that the file had to be converted to bytes
private void sendFile(Uri data) {
mParent.showProgress();
MultipartBody.Part file = packFile(view.getContext(), "audio[file]", data);
GeoService.saveSound(file, SoundResponseCallback, getAuthToken());
}
@Nullable
public static MultipartBody.Part packFile(@NonNull Context context, @NonNull String partName, @Nullable Uri fileUri) {
if (fileUri == null) return null;
ContentResolver cr = context.getContentResolver();
String tp = cr.getType(fileUri);
if (tp == null) {
tp = "audio";
}
try {
InputStream iStream = context.getContentResolver().openInputStream(fileUri);
byte[] inputData = getBytes(iStream);
RequestBody requestFile = RequestBody.create(MediaType.parse(tp), inputData);
return MultipartBody.Part.createFormData(partName, fileUri.getLastPathSegment(), requestFile);
} catch (Exception e) {
return null;
}
}
@Nullable
private static byte[] getBytes(@Nullable InputStream inputStream) throws IOException {
if (inputStream == null) return null;
ByteArrayOutputStream byteBuffer = new ByteArrayOutputStream();
int bufferSize = 1024;
byte[] buffer = new byte[bufferSize];
int len = 0;
while ((len = inputStream.read(buffer)) != -1) {
byteBuffer.write(buffer, 0, len);
}
return byteBuffer.toByteArray();
}