I make 1 page parallax site with MCV Model and i want to send all of data of pages to index_view load->view($filename,$data);
as 1 $data
. I can send all data as load->view($filename,$data_index,$data_about,$data_services,$data_contact);
But I think that the way isn't good way. I want to show may site structure.
I have Index_model.php (Model), index.php (Controller) and index_view.php (view) files.
There are navigation Links and index page slogan text functions in Index_model.php:
public function nav(){
$sql = "SELECT * FROM nav";
$sth = $this->db->select("SELECT * FROM nav");
return $sth;
}
public function slogan()
{
$sql = "SELECT * FROM slogan";
$row = $this->db->select($sql);
return $row;
}
Index.php (Controller) page so that..
public function Index(){
// Include Index_Model
$index_model = $this->load->model("index");
// Call Navigation Links functions
$nav = $index_model->nav();
$default = $this->defaults();
// Call slogans
$slogan = $index_model->slogan();
$this->load->view('index', $nav, $default);
}
and View part of Load.php is so..
public function view($filename,$data = false, $default = false){
include('app/view/'.$filename."_view.php");
}
How can i send my all value to view with 1 $variable. Is it possible. How is made Parallax site in MVC model?
You can put the variables in another array and pass the new array. like this
public function Index(){
// Include Index_Model
$index_model = $this->load->model("index");
// Call Navigation Links functions
$nav = $index_model->nav();
$default = $this->defaults();
// Call slogans
$slogan = $index_model->slogan();
$data=[];
$data['nav']=$nav;
$data['default']=$default;
$this->load->view('index', $data);
}