is this possible? I want to write an ajax function, that I do not want to duplicate it. Pass it different parameter which are locations to different files. Then use the promise to make them into one object. I would possible use the spread operator. is this possible.
var myFuncCalls = 0;
let promiseAjax = new Promise (function ( resolve,reject) {
//possibly use a for look to grab the number of times the loadDoc was called then call the same function and send it to may be an array?
function loadDoc(location) {
myFuncCalls++;
console.log("loadDoc was called :" + myFuncCalls);
var xyz = new XMLHttpRequest();
xyz.onreadystatechange = function () {
if (this.readyState == 4 && this.status == 200) {
//console.log(this.responseText)
resolve(this.responseText);
}
};
xyz.open("GET", location, true);
xyz.send();
}
loadDoc("/_js/someitems.json");
loadDoc("/_js/someMoreItems.json");
})
// then grab all that stuff and make one single object using spread operators
promiseAjax.then(function (fromResolve){
// JSON.parse(fromResolve);
var newObj = JSON.parse(fromResolve);
console.log(newObj);
})
with Promise.all
and Object.assign
,
function loadDoc(location) {
return new Promise((resolve, reject) => {
var xyz = new XMLHttpRequest();
xyz.onreadystatechange = () => {
if (this.readyState == 4 && this.status == 200) {
resolve(JSON.parse(this.responseText));
} else {
// resolving with empty object to avoid breaking other fetch if one failed
resolve({});
}
};
xyz.open("GET", location, true);
xyz.send();
});
}
const loadDocs = (paths) => Promise.all(paths.map(path => loadDoc(path))
.then(results => {
// combine all result into single object
return Object.assign({}, ...results);
}));
// example
loadDocs([
"/_js/someitems.json",
"/_js/someMoreItems.json"
]).then(function(finalCombinedObject) {
// other logic here
});