I need to replace characters. B for V and vice versa, Z for S and vice versa in Oracle
DECLARE
lc_word_so VARCHAR2 (500);
lc_word_lst VARCHAR2 (500);
lc_word VARCHAR2 (500) := 'VBZ';
ln_length NUMBER := LENGTH (lc_word);
lc_search VARCHAR2 (2);
lc_replace VARCHAR2 (2);
TYPE typ_search IS VARRAY (6) OF VARCHAR2 (1);
arr_search typ_search := typ_search ('B','V','S','Z');
BEGIN
IF ln_length > 0 THEN
lc_word_so := NULL;
FOR i IN 1 .. arr_search.COUNT LOOP
IF MOD (i, 2) = 0 THEN
lc_search := arr_search (i);
lc_replace := arr_search (i - 1);
ELSE
lc_search := arr_search (i);
lc_replace := arr_search (i + 1);
END IF;
FOR j IN 0 .. ln_length LOOP
lc_word_lst := lc_word_so;
lc_word_so := REGEXP_REPLACE (lc_word, lc_search, lc_replace, 1, j, 'i');
IF lc_word_so = lc_word THEN
EXIT;
ELSE
IF (lc_word_lst IS NULL OR lc_word_lst != lc_word_so) THEN
DBMS_OUTPUT.put_line (lc_word_so);
END IF;
END IF;
END LOOP;
END LOOP;
END IF;
END;
I expect the output: BBS BBZ BVS BVZ VBS VBZ VVS VVZ
But the actual output is: VVZ BBZ VBS
This is the solution using translate
, but it looks unprofessional:
SELECT TRANSLATE ('VBZ', 'B', 'V') FROM DUAL
UNION
SELECT TRANSLATE ('VBZ', 'V', 'B') FROM DUAL
UNION
SELECT TRANSLATE ('VBZ', 'S', 'Z') FROM DUAL
UNION
SELECT TRANSLATE ('VBZ', 'Z', 'S') FROM DUAL
UNION
SELECT TRANSLATE ('VBZ', 'BV', 'VB') FROM DUAL
UNION
SELECT TRANSLATE ('VBZ', 'VB', 'BV') FROM DUAL
UNION
SELECT TRANSLATE ('VBZ', 'SZ', 'ZS') FROM DUAL
UNION
SELECT TRANSLATE ('VBZ', 'ZS', 'SZ') FROM DUAL
UNION
SELECT TRANSLATE ('VBZ', 'BS', 'VZ') FROM DUAL
UNION
SELECT TRANSLATE ('VBZ', 'VZ', 'BS') FROM DUAL
UNION
SELECT TRANSLATE ('VBZ', 'SB', 'ZV') FROM DUAL
UNION
SELECT TRANSLATE ('VBZ', 'ZV', 'SB') FROM DUAL
UNION
SELECT TRANSLATE ('VBZ', 'BV', 'VB') FROM DUAL
UNION
SELECT TRANSLATE ('VBZ', 'VBZ', 'BVS') FROM DUAL
UNION
SELECT TRANSLATE ('VBZ', 'VZS', 'BSZ') FROM DUAL
UNION
SELECT TRANSLATE ('VBZ', 'BZS', 'VSZ') FROM DUAL
UNION
SELECT TRANSLATE ('VBZ', 'BVZS', 'VBSZ') FROM DUAL
UNION
SELECT TRANSLATE ('VBZ', 'VBZS', 'BVSZ') FROM DUAL