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phparraysstr-replace

Replace Array with Numbers and text

My code is a simple code but i not seing what the problem might be.

I'm doing a "for" to get a number from 1 to 2000, then replacing the number into text, example '1px','2px',...

Then i set this "'1px','2px',..." in a array. For that reason i could verify where in the text has "px" , then i could repalce it with "%". PS: "%" is also an array.

To replace the text, i use str_replace, and it funcional, but not when i use it with my code.

$search = array('150px','151px','152px','153px','154px',...);
$replace = array('100%');
$testes = str_replace($search, $replace, $GetText)

Example of $GetText - <p><img src="data:image/png;base64,iVBOC" data-filename="andy-brown_4.png" style="width: 150px;"><br></p>

this codes work

Now the code that im trying,

for($i = 1; $i<=2000; $i++) {
  echo "'". $i . 'px' . "'," ;
  $test = "'". $i . 'px' . "'," ;
}

Show all the number from 1 until 2000 with text, example: '274px', enter image description here

$search = array($test);
$replace = array('100%');
$testes = str_replace($search, $replace, $GetText)

With this process, it doesnt replace the "px" with "%"

enter image description here

Solution

  • You can solve your task with one php function preg_replace

    $GetText = '<p><img src="data:image/png;base64,iVBOC" data-filename="andy-brown_4.png" style="width: 150px;"><br></p>';

$result = preg_replace("/\d{1,4}px/","100%",$GetText);

var_dump($result);

    What \d{1,4}px mean is: \d - search for digit, {1,4} - previous element (e.g. digit) must be repeated from 1 to 4 times, px - must be folowed by this text,

    So it looks for everything like *px and replace it with 100%, where * is any number from 0 to 9999;