This is related to Simon's question on changing default ColorData in Mathematica. While the solutions all addressed the issue of changing ColorData
in line plots, I didn't quite find the discussion helpful in changing the ColorFunction
/ColorData
in ContourPlot
/ArrayPlot
/Plot3D
, etc.
TLDR: Is there a way to get mma to use custom colors in ArrayPlot/ContourPlot/etc.
sin(x^2+y^3)
that I created in MATLAB:
Now doing the same in mma as:
xMax = 3; yMax = 3;
img = Transpose@
Table[Sin[y ^3 + x^2], {x, -xMax, xMax, 0.01}, {y, -yMax, yMax,
0.01}];
plot = ArrayPlot[img, ColorFunction -> ColorData["Rainbow"],
AspectRatio -> 1,
FrameTicks -> {FindDivisions[{0, (img // Dimensions // First) - 1},
4], FindDivisions[{0, (img // Dimensions // Last) - 1}, 4],
None, None},
DataReversed ->
True] /. (FrameTicks -> {x_,
y_}) :> (FrameTicks -> {x /. {a_?NumericQ, b_Integer} :> {a,
2 xMax (b/((img // Dimensions // First) - 1) - 1/2)},
y /. {a_?NumericQ, b_Integer} :> {a,
2 yMax (b/((img // Dimensions // Last) - 1) - 1/2)}})
I get the following plot:
I prefer the rich, bright colors in MATLAB to mma's pastel/dull colors. How do I get mma to use these colors, if I have the RGB values of the colormap from MATLAB?
You can download the RGB values of the default colormap in MATLAB, and import it into mma as
cMap = Transpose@Import["path-to-colorMapJet.mat", {"HDF5",
"Datasets", "cMap"}];
cMap
is a 64x3
array of values between 0
and 1
.
Just to give you some background, here's some relevant text from the MathWorks documentation on colormap
A colormap is an m-by-3 matrix of real numbers between 0.0 and 1.0. Each row is an RGB vector that defines one color. The kth row of the colormap defines the kth color, where map(k,:) = [r(k) g(k) b(k)]) specifies the intensity of red, green, and blue.
Here map=cMap
, and m=64
.
I tried poking at ColorDataFunction
, and I see that the ColorData
format is similar to the colormap
. However, I'm not sure how to get ArrayPlot
to use it (and presumably it ought to be the same for other plot functions).
Also, since my exercise here is purely to reach a level of comfort in mma, similar to what I have in MATLAB, I'd appreciate comments and suggestions on improving my code. Specifically, I'm not too satisfied with my hack of a way to "fix" the FrameTicks
... surely there must be a nicer/easier way to do it.
Replace your ColorData["Rainbow"]
with this one:
Function[Blend[RGBColor @@@ cMap, Slot[1]]]
and you get this:
As to your second question, you can do it this way:
xMax = 3; yMax = 3;
img = Transpose@
Table[Sin[y^3 + x^2], {x, -xMax, xMax, 0.01}, {y, -yMax, yMax,
0.01}];
plot = ArrayPlot[img,
ColorFunction -> Function[Blend[RGBColor @@@ cMap, Slot[1]]],
AspectRatio -> 1, FrameTicks -> Automatic,
DataRange -> {{-xMax, xMax}, {-yMax, yMax}}, DataReversed -> True]
but why don't you use DensityPlot?
DensityPlot[Sin[y^3 + x^2], {x, -xMax, xMax}, {y, -yMax, yMax},
ColorFunction -> Function[Blend[RGBColor @@@ cMap, Slot[1]]],
PlotPoints -> 300]
EDIT
Note that in the second plot the y-range labeling is reversed. That's because it takes the DataReversed setting into account. ArrayPlot plots the rows of the arrays in the same order as they appear when the array's content is printed on screen. So the first row is plotted on top and the last row is plotted at the bottom. High row values correspond to low y-values and vice versa. DataReversed->True corrects for this phenomenon, but in this case it also 'corrects' the y values. A workaround is to fill the array starting from high y-values going down to the lower ones. In that case you don't need DataReversed:
xMax = 3; yMax = 3;
img = Transpose@
Table[Sin[y^3 + x^2], {x, -xMax, xMax, 0.01}, {y,
yMax, -yMax, -0.01}];
plot = ArrayPlot[img,
ColorFunction -> Function[Blend[RGBColor @@@ cMap, Slot[1]]],
AspectRatio -> 1, FrameTicks -> Automatic,
DataRange -> {{-xMax, xMax}, {-yMax, yMax}}]