I have two RDDs have common variables, which have format like:
x = sc.parallelize([("A", 1), ("B", 4),("A",2)])
y = sc.parallelize([("A", -1),("B", 5)])
Then I want to group with them using the common variable. "A"
and "B"
.
I have tried to use the command below:
z = [(x, tuple(map(list, y))) for x, y in sorted(list(x.cogroup(y).collect()))]
print(z)
What I got is
[('A', ([1, 2], [-1])), ('B', ([4], [5]))]
However, the thing I want is
[('A', ([1], [-1])), ('B', ([4], [5])),('A', ([2], [-1]))]
How can I change the code to get the output like above? Thank you.
You can do this with a straight join:
print(x.join(y).collect())
#[('A', (1, -1)), ('A', (2, -1)), ('B', (4, 5))]
Add in a call to mapValues
if you want the elements of the tuple
s to be list
s:
print(x.join(y).mapValues(lambda a: tuple([b] for b in a)).collect())
#[('A', ([1], [-1])), ('A', ([2], [-1])), ('B', ([4], [5]))]