AWK, rename string only on n-th line after pattern match

Question

Hi i have problem i cannot rename just only 1st occurence placed on 9th row of string after/since matched pattern

this is input (file containing 30k lines):

This is pattern 
patternvalue=dom.value.5.row.2
design=12
face=x1-m
omit=11
mode=OFF
option=955
display=x1-11-OFF
type=2
name=8a9s7fa645sdf              
resolution=0    
prio=OK 
number of pattern values:   
pattern values  
id=hex00.EA 
name=4fda6sd4f                  
number of pattern values:   
id=hex00.EF 
name=as7e8w87e                  
patternvalue=dom.value.5.row.8
design=1
face=x1-n
omit=12
mode=OFF
option=95
display=x1-22-ON
type=2
name=8a9sad8f               
resolution=0    
prio=OK 
number of pattern values:   
pattern values  
id=hex00.0A 
name=dsf79                  
number of pattern values:   
id=hex00.AA 
name=777777s                
number of pattern values:   
id=hex00.BB 
name=777777l                
number of pattern values:   
id=hex00.CC 
name=777777m                

i tried this, but its renaming on all strings "name"

 awk '/This is pattern/ && NR==10 ; sub(/name/,"patternname")1' num 

"_https://stackoverflow.com/questions/51678717/print-mth-column-of-nth-line-after-a-match-if-found-in-a-file-using-awk"

This is expected output:

This is pattern 
patternvalue=dom.value.5.row.2
design=12
face=x1-m
omit=11
mode=OFF
option=955
display=x1-11-OFF
type=2
patternname=8a9s7fa645sdf           
resolution=0    
prio=OK 
number of pattern values:   
pattern values  
id=hex00.EA 
name=4fda6sd4f                  
number of pattern values:   
id=hex00.EF 
name=as7e8w87e                  
This is pattern 
patternvalue=dom.value.5.row.8
design=1
face=x1-n
omit=12
mode=OFF
option=95
display=x1-22-ON
type=2
patternname=8a9sad8f                
resolution=0    
prio=OK 
number of pattern values:   
pattern values  
id=hex00.0A 
name=dsf79                 
number of pattern values:   
id=hex00.AA 
name=777777s                
number of pattern values:   
id=hex00.BB 
name=777777l                
number of pattern values:   
id=hex00.CC 
name=777777m    

Thank you for any hints

Answer 1

Something like this should be ok:

awk '/This is pattern/{n=NR};NR==n+9{sub(/name/,"patternname")};1'

Some comments about your try. You wrote

awk '/This is pattern/ && NR==10 ; sub(/name/,"patternname")1' num

awk commands follow the pattern

condition1{action1};condition2{action2};....

If the {action} part is missing, the default action is {print}.

If the condition part is missing, the default condition is 1 (=always true)

As a result , your awk script equals to this:

awk '/This is pattern/ && NR==10{print};sub(/name/,"patternname"){print};1{print}'

Moreover, awk internal variable NR holds the line number being processed of the input file.

As a result the first part of your script '/This is pattern/ && NR==10{print} prints the line only when This is pattern found and NR (line number) is 10 meaning never in your case.

The second part of your script sub(/name/,"patternname"){print}, uses the function sub as a condition to print the line. So for every line being processed, sub tries to replace name with patternname. if this replacement is sucessfull , the line is then {print}.

The third part of your script 1{print} , prints all the other lines, since the condition is 1 (always true).

About my solution:

First part /This is pattern/{n=NR}, holds in a temp variable n the line number NR in which This is pattern was found.

Second part NR==n+9{sub(/name/,"patternname")} compares NR (line number being processed by awk) to n+9 (line number of This is Pattern + 9 more lines), and when this condition becomes true, then name is replaced by patternname using sub which is enclosed in {...} to dictate that this is the action part of the NR==n+9 condition.

Third part 1 , just prints all the other lines (condition 1==true , action is missing , default action {print} is performed)