how to find in java string case incesitive number of word java

Question

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       String test1 = "java java java. JAVA! ";
       String test2 = "h w !!! ...";
       String word ="java";
       int count = 0;

      String strArray[] = test2.split(" ");

      for(int i=0; i < strArray.length; i++){
            if (word.equals("java")) {
                `enter code here`   
                 count++;
            }            
            System.out.println(strArray[i]);
      }

    System.out.println(count);
    test1.toUpperCase() + test1.toLowerCase().concat;
    count++;
    test1.toLowerCase();
    count++;
    System.out.println(count);

how to return the occurrences in java case insensitive in java i would been trolling the internet but no luck. In JavaScript i would use are but here i am new so please help. So i need to find as above suggested how many times java case insensitive occurs

Answer 1

hopefully this helps

String inputString = "java java java. JAVA!";

        int counter = 0;
        Pattern pattern = Pattern.compile("JAVA");
        Matcher match = pattern.matcher(inputString.toUpperCase());
        while (match.find()) {
            counter++;
        }

        System.out.println(counter);