I have created a small search bar which will generate movie details but I want the results to open in a separate html page can you guys please help me this problem?
My code is below
<div class="form-container">
<form method="POST">
<div class="search-container">
<input type="text" name="search" placeholder="Search...">
<button class="btn btn-primary" type="submit" name="submit-search">Search</button>
</div>
</form>
<div class="resutls">
<?php
if (isset($_POST['submit-search'])) {
$txtresult = $_POST['search'];
if ($txtresult == 'red') {
echo "<span class= 'red'>".$txtresult."</span><br>";
}elseif ($txtresult == 'green') {
echo "<span class= 'green'>".$txtresult."</span><br>";
}
function getImdbRecord($title, $ApiKey)
{
$path = "http://www.omdbapi.com/?t=$title&apikey=$ApiKey";
$json = file_get_contents($path);
return json_decode($json, TRUE);
}
$data = getImdbRecord($txtresult, "f3d054e8");
echo "<span class = 'info-box'><h3> Name :".$data['Title']."</h3><h3> Year : ".$data['Year']."</h3><h3> Duration : ".$data['Runtime'],"</h3></span>";
}
?>
</div>
You need to use the action parameter in form tag to specify a different HTML/PHP Page.
<form action="otherFile.php" method="POST">
Then you need to move the code to fetch results to otherFile.php