How to select from multiindex based on individual values in several columns?

Question

I have a dataframe created like this:

import pandas as pd

df = pd.DataFrame({
    'ind1': list('AAABBBCCC'),
    'ind2': list(map(int, list('123123123'))),
    'val1': [0, 0, 0, -1, -4, 5, 10, 11, 4],
    'val2': [0.1, 0.2, -0.2, 0.1, 0.2, 0.2, -0.1, 2, 0.1]
})

df = df.set_index(['ind1', 'ind2'])

Resulting data:

           val1  val2
ind1 ind2            
A    1        0   0.1
     2        0   0.2
     3        0  -0.2
B    1       -1   0.1
     2       -4   0.2
     3        5   0.2
C    1       10  -0.1
     2       11   2.0
     3        4   0.1

I want to select all entries where:

1. At least one item in val1 is unequal 0
2. Each absolute value in val2 is < 0.5

In the example above, therefore only

B    1       -1   0.1
     2       -4   0.2
     3        5   0.2

should remain.

I cannot use sum() as the values can be positive and negative, so something like this

df.reset_index().groupby('ind1').sum()

      ind2  val1  val2
ind1                  
A        6     0   0.1
B        6     0   0.5
C        6    25   2.0

would not work.

How would I use any() and all() here?

Answer 1

Without lambda by transform

s1=df.val1.ne(0).groupby(level=0).transform('any')
s2=df.val2.abs().lt(0.5).groupby(level=0).transform('all')
df[s1&s2]
Out[583]: 
           val1  val2
ind1 ind2            
B    1       -1   0.1
     2       -4   0.2
     3        5   0.2