I am trying to modify a script to take in arguments so I can run the script and it cycles through a number of csv files and produces the results.
However I am falling down early on when trying to just run the what was working code with an argument instead of hard coded using sys.argv instead of schema.csv
I am running the script out of the code directory which is where the schema.csv is but I am getting this error.
FileNotFoundError: [Errno 2] No such file or directory: "['schema.csv']"
I have double checked the working directory with os.getcwd(), my thought is that the result highlighted in the error has too many quotation marks or brackets but I am not sure on what I can test.
import sys
def get_schema(table):
with open(str(sys.argv[1:])) as f:
i = 0
for line in f:
column = line.split(',')
datatype='STRING'
if (column[0] == table):
if 'char' in column[2]:
datatype = 'STRING'
elif 'int' in column[2]:
datatype = 'INTEGER'
elif 'boolean' in column[2]:
datatype = 'BOOLEAN'
elif 'timestamp' in column[2]:
datatype = 'TIMESTAMP'
elif 'numeric' in column[2]:
datatype = 'NUMERIC'
elif 'date' in column[2]:
datatype = 'DATE'
if (i == 0):
print('#%s' %(table))
print ('[')
i = i + 1
if (i == 1):
print ('{"name":"%s", "mode": "NULLABLE", "type": "%s"}' %(column[1],datatype))
if (i > 1):
print (',{"name":"%s", "mode": "NULLABLE", "type": "%s"}' %(column[1],datatype))
i = i + 1
print(',{"name":"ExtractAuditKey", "mode": "NULLABLE", "type": "INTEGER"}')
print (']')
get_schema(table=(sys.argv[1:]))
FileNotFoundError: [Errno 2] No such file or directory: "['schema.csv']"
with open(str(sys.argv[1:])) as f:
will not work as you hope here. You're using sys.argv[1:]
which gives you a list by "slicing", rather than a string. If you're only inputting one value, you can do sys.argv[1]
instead and it should work - indexing gives the entry, slicing gives a list.