I'm reading from the stdin. The user is promoted to eather type one digit or to type three. Which functions are good this problem?
I have tried
int in[3] = {-1, -1, -1};
scanf("%d %d %d", &in[0], &in[1], &in[2]);
printf("%d, %d, %d\n", in[0], in[1], in[2]);
This works great for three digits but not if only one is typed.
I want to have e.g. the input to be "17" or "0 1 9" The output should be then e.g.
int amount = 1
int digits[3] = {17, -1, -1}
or
int amount = 3
int digits[3] = {0, 1, 9}
You are close to what you want, but you read int rather than string so
char *in[3] = {-1, -1, -1};
must be
int in[3] = {-1, -1, -1};
also allowing to have -1 as valid initial values.
This works great for three digits but not if only one is typed.
doing scanf("%d %d %d", &in[0], &in[1], &in[2]);
to finish you need to enter 3 valid int or to finish on erro ro reach EOF or give invalid input, to be able to only enter one value do a fgets then _a __sscanf_
I want to have e.g. the input to be "17" or "0 1 9" The output should be then e.g.
int amount = 1 int digits[3] = {17, -1, -1}
or
int amount = 3 int digits[3] = {0, 1, 9}
do for instance
#include <stdio.h>
int main(void)
{
char line[32];
if (fgets(line, sizeof(line), stdin) == line) {
int ints[3] = { -1, -1, -1 };
int amount = sscanf(line, "%d %d %d", &ints[0], &ints[1], &ints[2]);
printf("%d : { %d %d %d }\n", amount, ints[0], ints[1], ints[2]);
}
return 0;
}
Compilation and executions
pi@raspberrypi:/tmp $ gcc -pedantic -Wall -Wextra c.c
pi@raspberrypi:/tmp $ ./a.out
pi@raspberrypi:/tmp $ ./a.out
17
1 : { 17 -1 -1 }
pi@raspberrypi:/tmp $ ./a.out
0 1 9
3 : { 0 1 9 }
pi@raspberrypi:/tmp $ ./a.out
1 a
1 : { 1 -1 -1 }
pi@raspberrypi:/tmp $ ./a.out
a
0 : { -1 -1 -1 }
pi@raspberrypi:/tmp $
pi@raspberrypi:/tmp $ ./a.out
-1 : { -1 -1 -1 }
pi@raspberrypi:/tmp $
(in the last case is an empty line, e.g. just enter)
I renamed digits to ints because digits let suppose each entry is a digit ('0' for instance) while you want integers