Time comparision in java

Question

I just get the time in HH:MM format and check if it is greater than 9:30 then count c is increased as 1.I just did for a single user input time.But i need to get multiple times from user and compare.If it is greater than 9:30 then increment the count values.First get n value and then get n no of time from user.How can i change my code to get the n no of time and compare that?

Scanner input = new Scanner(System.in);
 String time = input.nextLine();
 System.out.println();
 int c=0;
String time2 = "9:30";
 DateFormat sdf = new SimpleDateFormat("hh:mm");
 Date d1 = sdf.parse(time);
 Date d2 = sdf.parse(time2);
 if(d1.after(d2))
 {
     c++;
}
System.out.println(c);

Answer 1

This should do it. It is a basic implementation, you can optimize it the way you like.

EDIT (with explanation comments):

Scanner sc = new Scanner(System.in);

// accept user input for N
System.out.println("Enter N");
int n = sc.nextInt();

String time;
int c = 0;

// store the DateFormat to compare the user inputs with
String time2 = "9:30";
DateFormat sdf = new SimpleDateFormat("hh:mm");
Date d2 = null;
try {
    d2 = sdf.parse(time2);
} catch (ParseException e) {
    e.printStackTrace();
}

// iterate for N times, asking for a user input N times.
for (int i = 0; i < n; i++) {
    // get user's input to parse and compare
    System.out.println("Enter Time");
    time = sc.next();
    Date d1 = null;
    try {
        d1 = sdf.parse(time);
    } catch (ParseException e) {
        e.printStackTrace();
    }
    if (d1.after(d2))  {
        c++;
    }
}
System.out.println(c);

I have not changed much of your code, just added a loop and did the same thing for N times. To quote from the comments above, "loops are your friend".

Hope this helps. Good luck. Comment if you have any further questions.