Hiding spinner buttons for a specific Jquery UI spinner

Question

I have a readonly JQuery UI spinner and I want to disable or hide the spinning buttons.

I saw from a previous question, that if I want to hide all spinner buttons I can use:

$('.ui-spinner .ui-spinner-button').css('display','none');

and it work great.

But how do I filter just one specific element?

I have tried

$('#specifcElement a.ui-spinner-button').css('display','none');

and also

$('.ui-spinner specificElement.ui-spinner-button').css('display','none')

without succes.

Answer 1

Spinner wraps the element upon initialization and it appears like so:

<span class="ui-spinner ui-corner-all ui-widget ui-widget-content" style="display: none;">
  <input id="spinner" name="value" class="spin ui-spinner-input" autocomplete="off" role="spinbutton">
  <a tabindex="-1" aria-hidden="true" class="ui-button ui-widget ui-spinner-button ui-spinner-up ui-corner-tr ui-button-icon-only" role="button">
    <span class="ui-button-icon ui-icon ui-icon-triangle-1-n"></span>
    <span class="ui-button-icon-space"> </span>
  </a>
  <a tabindex="-1" aria-hidden="true" class="ui-button ui-widget ui-spinner-button ui-spinner-down ui-corner-br ui-button-icon-only" role="button">
    <span class="ui-button-icon ui-icon ui-icon-triangle-1-s"></span>
    <span class="ui-button-icon-space"> </span>
  </a>
</span>

So to hide the spinner objects we can select the text field and then select it's Parent element.

Consider the following:

$(function() {
  $(".spin").spinner();

  $("#spinner-2").parent().add("label[for=spinner-2]").hide();
});

.spin-wrap {
  width: 340px;
}

.spin-wrap .ui-spinner {
  margin-bottom: 3px;
}

<link rel="stylesheet" href="//code.jquery.com/ui/1.12.1/themes/base/jquery-ui.css">
<script src="https://code.jquery.com/jquery-1.12.4.js"></script>
<script src="https://code.jquery.com/ui/1.12.1/jquery-ui.js"></script>

<div class="spin-wrap">
  <label for="spinner-1">Select value 1:</label>
  <input id="spinner-1" name="value[1]" class="spin">
  <label for="spinner-2">Select value 2:</label>
  <input id="spinner-2" name="value[2]" class="spin">
  <label for="spinner-3">Select value 3:</label>
  <input id="spinner-3" name="value[3]" class="spin">
</div>

Here you can see that $("#spinner-2") is just selecting the input element. I then used .parent() to select the spinner itself. I also used .add() to add the label element to the object so it is hidden too.